quote:Um, what? When the coil flips over, its North and South poles flip over as well, just like would happen if it were a permanent magnet.
When the coil flips over the axis of rotation is reversed,
quote:????
Originally posted by dem:
EMag, ReMag, DMag, CMag
quote:Well, it wasn't a reliable motor. We were constantly fiddling with it to get it working again.
it doesn't seem to me that "the contact is lost and it coasts through" would make a reliable motor
quote:Whether there's a ferrous core or not, the direction of the magnetic north pole is determined by the direction that current flows through the loops, according to the right-hand rule. The ferrous core mostly just makes it easier to add together the magnetic fields from a bunch of loops
Looking at the coil, I find it difficult to imagine the axis of the magnetic field. I think that may be the key. In a traditional electromagnet, the wire is wrapped sequentially around an iron core, which fixes the polarity of the axis along the length of the core. Here there is only a bundled loop of wire, with no core. What causes the north end of the field to project from one particular end of the loop?
quote:The North-South axis of that magnet is coaxial with the circle, so when it's laying down, as in the motor, either the North or South pole is sticking straight up.
Also, the circular magnet is lying on its side. Which direction do the magnetic lines project?
code:When the half-circle is in the down position, the force is into the screen, taking the current as running right to left and the magnetic field as going straight up. When the half-circle is in the up position, the force is likewise into the screen. But, because it is further away from the magnet, the force is weaker; therefore, neglecting friction, it is not braked as hard as it was pushed, and continues through to reach the down position and get another kick. The full coil can be considered as consisting of many half-circles.--<-| |-<--
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MAGNET
quote:Almost right, You're failing to take into account the direction of current on the other half of the loop.
Originally posted by King of Men:
When the half-circle is in the down position, the force is into the screen, taking the current as running right to left and the magnetic field as going straight up. When the half-circle is in the up position, the force is likewise into the screen. But, because it is further away from the magnet, the force is weaker; therefore, neglecting friction, it is not braked as hard as it was pushed, and continues through to reach the down position and get another kick. The full coil can be considered as consisting of many half-circles.
code:In both the above time frames of the loop the magnitude of the Torque generated is equal, but opposite in direction, averaging out to zero over time.|---->-----|
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MAGNET
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MAGNET
quote:Yes. I've built a few of these. You can get one in kit form too: http://www.scientificsonline.com/worlds-simplest-motor-kit.html
Is this motor sustainable?
quote:I'd recommend going with something a little safer.
Originally posted by DSH:
Try a homoploar motor (which is really the worlds simplest motor )
quote:When it's working? Yes.
Is this motor sustainable? (i.e. if you start spinning the coil does it continue to spin indefinitely?)
quote:Yes, I realised this after going to bed. I observe that one of the two half-circles has to have one more strand of wire than the other, so there is an asymmetry. But I don't know whether that's sufficient to overcome the friction; it depends on the strength of the magnet.
Almost right, You're failing to take into account the direction of current on the other half of the loop.
quote:Ah yes, I see that now.
Originally posted by King of Men:
quote:Yes, I realised this after going to bed. I observe that one of the two half-circles has to have one more strand of wire than the other, so there is an asymmetry. But I don't know whether that's sufficient to overcome the friction; it depends on the strength of the magnet.
Almost right, You're failing to take into account the direction of current on the other half of the loop.
quote:I know I'm not KoM but I think I can address your post. As per KoM's diagram, at any point in the rotation the electromagnetic force pushes into the screen. However, since the Torque is derived from the portion of the force that is normal to the plane formed by the wire and the axis of rotation, any point at which the wire is below the axis in elevation causes one direction of torque, while the opposite direction is caused when the wire is above the axis. The magnitude of the electromagnetic force is dependent on the intensity of the magnetic flux, thus the torque created when the wire is below the axis (closer to the magnet) will be greater than the torque created when it is above the axis.
Originally posted by mr_porteiro_head:
KoM -- could you reply to my response to your half-loop idea?
quote:But the net current has to be from + to -, regardless of the path of least resistance. If both ends of the wire are on the same terminal which must be the case for the coil to be symmetric (as indicated in the instructions), There is no driving force for flow around the coil. There is only a driving force toward the opposite pole.
Originally posted by Dobbie:
The current does flow around the coil. If it were a solid metal ring the current would flow straight from positive to negative, but with a wire the current flows along the path of least resistance, which is along the wire.
quote:Electrons flow from negative to positive. Current moves in the opposite direction of the electrons. Damn Ben Franklin.
Originally posted by Dobbie:
Actually that should be "from the negative end to the [/i]positive[/i] end".
quote:Yes, that's what I'm saying. The current flowing in the copper wire will be from the positive terminal to the negative terminal along both sides of the copper coil because that's direction of the EM force. If you attached one end of the wire to one terminus and the other end to the other terminus, the current would flow around the coil. But that isn't what is being done in this experiment. One side of the coil is attached to the the + terminus, the other side of the coil is attached to - terminus. As long as the coil is symmetric, there is no driving force for electrons to flow around the coil.
Originally posted by Dobbie:
The electromotive force drives the current through the wire from the positive end of the battery to the negative end, no matter what shape the wire is wound into.
code:If the coil didn't consist of a single wire, but rather of a bunch of wires all of which were connected to the terminals separately, then in effect you've got two resistors connected in parallel. Consequently the current flows through the top and bottom loops in the same direction, right to left. Then the force due to the magnetic field is into the screen on both parts of the coil, so as far as rotation goes they oppose each other; but because of the aforementioned asymmetry due to distance from the magnet, there is a net torque.|------<-------|
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quote:That would be true of a solid ring of copper, not a coil of copper wire. The copper atoms are bonded to each other along the length of the wire. The current flows more easily along these bonds, so the current tends to follow the path of the wire, even when the wire comes into contact with itself.
Originally posted by The Rabbit:
The current flowing in the copper wire will be from the positive terminal to the negative terminal along both sides of the copper coil..
quote:I just read the directions more closely and it looks like your initial interpretation was correct. The wire doesn't look to me like its insulated. What are the chances that the contact between the loops of the coil is good enough that current actually flows the way I'd initially assumed.
Originally posted by King of Men:
I think you are visualising something wrong. (Or else I am.) There is a single wire forming both the coil and the connections; this is not obvious in the picture because the connections have had the insulation stripped off, so it looks different, but it's all one wire. So there is a wire with one end at each terminus.
quote:The instructions explicitly call for stripping off the insulation at the ends; it's common for insulation on lab wire to be a very thin coat of varnish, not obvious if you don't know what you're looking for. But at this point I think we had better wait for Squicky to give us more information about the construction.
The wire doesn't look to me like it's insulated.
quote:Yes, but when you make a regular solenoid, you don't tie the opposite sides together with the wire. That will reduce the contact resistance between the wires. It appears that the combined resistance of a bunch of strips of wire short wire in parallel + contact resistance is less than the resistance of one long thin wire. If it weren't, this motor couldn't work.
Originally posted by MattP:
The coil is a spiral. Imagine taking a long wire and wrapping it many times around a cylinder. The current will be flowing through one end of the wire, around the coil several times in the same direction, then exit through the other end of the wire.
quote:You could just use an Ohmmeter to test this.
Originally posted by The Rabbit:
quote:Yes, but when you make a regular solenoid, you don't tie the opposite sides together with the wire. That will reduce the contact resistance between the wires. It appears that the combined resistance of a bunch of strips of wire short wire in parallel + contact resistance is less than the resistance of one long thin wire. If it weren't, this motor couldn't work.
Originally posted by MattP:
The coil is a spiral. Imagine taking a long wire and wrapping it many times around a cylinder. The current will be flowing through one end of the wire, around the coil several times in the same direction, then exit through the other end of the wire.
We could design some experiments to test my theory. Try loosening the coil to decrease the contact between the wire loops. If I'm right, the motor will stop working.
quote:From these instructions I see that the insulation is only removed on one half of the wire that is touching the conducting supports. This would cause the wire loop to conduct only half of the time in the spin, thus the opposite half of the spin would get no current and thus no forces to oppose that of the conducting half.
Originally posted by MattP:
The instructions here demonstrate the construction of the coil: http://www.stmary.ws/highschool/physics/home/lab/lab3/Electromagnetism_Lab_latest_files/image003.jpg
quote:for the magnetic field generated by the coil, point your right thumb in the direction of the current and imagine your hand tangential to the loop. Coil your fingers through the loop, the side of the hole in the loop your fingers are coming out of is the North face, the side of the hole your fingers are entering the hole is the south face.
Originally posted by The Rabbit:
I'm trying to get a clear picture of how the magnetic field lines would go in this motor and its not intuitively obvious.
The current wouldn't flow around the wire coil. It's going to flow the same direction (+ to -) along each half loop. For it to work, each half of the ring has to be attracted as it approaches the magnet and repelled once it crosses the center of the magnet. Now I just need to get a clearer grasp of how the magnetic field lines go on a ring magnet. Isn't one pole in the center of the ring and the other pole on the outside of the ring? If that's the case, once a half loop passes the center of the ring magnet, the direction of the magnetic field flips, so it will be repelled rather than attracted?
Electromagnetism is one of my weaker areas so I could be completely wrong here.
quote:Yes that occurred to me after I made the post. Sadly, I don't have a spool of magnet wire and an Ohm meter in my desk drawer to test it out.
Originally posted by MEC:
quote:You could just use an Ohmmeter to test this.
Originally posted by The Rabbit:
quote:Yes, but when you make a regular solenoid, you don't tie the opposite sides together with the wire. That will reduce the contact resistance between the wires. It appears that the combined resistance of a bunch of strips of wire short wire in parallel + contact resistance is less than the resistance of one long thin wire. If it weren't, this motor couldn't work.
Originally posted by MattP:
The coil is a spiral. Imagine taking a long wire and wrapping it many times around a cylinder. The current will be flowing through one end of the wire, around the coil several times in the same direction, then exit through the other end of the wire.
We could design some experiments to test my theory. Try loosening the coil to decrease the contact between the wire loops. If I'm right, the motor will stop working.
quote:I'm fine with that in two dimensions. My difficulty is visualizing what happens in the third dimension. The field strength drops off by distance squared, so because the distance between the permanent magnet and the coil is much smaller (at closest approach) than the diameter of the coil or the permanent magnet, what the magnet field lines are doing around the edges of the coil and center of the permanent magnet matters -- doesn't it?
for the magnetic field generated by the coil, point your right thumb in the direction of the current and imagine your hand tangential to the loop. Coil your fingers through the loop, the side of the hole in the loop your fingers are coming out of is the North face, the side of the hole your fingers are entering the hole is the south face.
quote:Yes, but the instructions at the web site MPH used, say to remove ALL the insulation from the wire. MPH did this, presuming it wouldn't work but it did -- hence the thread.
Originally posted by MEC:
quote:From these instructions I see that the insulation is only removed on one half of the wire that is touching the conducting supports. This would cause the wire loop to conduct only half of the time in the spin, thus the opposite half of the spin would get no current and thus no forces to oppose that of the conducting half.
Originally posted by MattP:
The instructions here demonstrate the construction of the coil: http://www.stmary.ws/highschool/physics/home/lab/lab3/Electromagnetism_Lab_latest_files/image003.jpg
quote:To be clear, he removed the insulation all the way around a small piece of the wire where it makes contact. The rest of the wire is insulated so the loops of the coil and the wrappings at each end are not actually creating shorts. The alternative (and more effective) construction method involves only removing the insulation from half of the wire in that small area.
Yes, but the instructions at the web site MPH used, say to remove ALL the insulation from the wire. MPH did this, presuming it wouldn't work but it did -- hence the thread.
quote:We will have to ask MPH to be sure, but the implication was that he removed all the way around the small piece of wire where it makes contact. He did not expect it to work this way but it did. We are looking for an explanation for why it would work at all this way.
Originally posted by MattP:
quote:To be clear, he removed the insulation all the way around a small piece of the wire where it makes contact. The rest of the wire is insulated so the loops of the coil and the wrappings at each end are not actually creating shorts. The alternative (and more effective) construction method involves only removing the insulation from half of the wire in that small area.
Yes, but the instructions at the web site MPH used, say to remove ALL the insulation from the wire. MPH did this, presuming it wouldn't work but it did -- hence the thread.
quote:Right. I was just making sure that we were on the same page now. There was a point at which it seemed like some people were under the impression that the entire length of wire was uninsulated.
We will have to ask MPH to be sure, but the implication was that he removed all the way around the small piece of wire where it makes contact. He did not expect it to work this way but it did. We are looking for an explanation for why it would work at all this way.
quote:Well, if you'd like I can see if I can take some time out to test it, as an Electrical Engineering student I have plenty of access to Ohmmeters.
Originally posted by The Rabbit:
Yes that occurred to me after I made the post. Sadly, I don't have a spool of magnet wire and an Ohm meter in my desk drawer to test it out.